2x^2+4x-286=02x

Solution for 2x^2+4x-286=02x equation:

2x^2+4x-286=02x

We move all terms to the left:

2x^2+4x-286-(02x)=0

We add all the numbers together, and all the variables

2x^2+2x-286=0

a = 2; b = 2; c = -286;
Δ = b2-4ac
Δ = 22-4·2·(-286)
Δ = 2292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2292}=\sqrt{4*573}=\sqrt{4}*\sqrt{573}=2\sqrt{573}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{573}}{2*2}=\frac{-2-2\sqrt{573}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{573}}{2*2}=\frac{-2+2\sqrt{573}}{4}
$